求解文中正则匹配'\'将''转义成字符串的原理，文中正转义,In [33]: re.

不想匹配到就加个 r。

re.match(r'ab\\*c','ab*cd')

'ab\\*c'

这个规则在 compile 之后确实就是

'ab*c' // 这里*表示匹配`*`这个字符

那么当然可以匹配目标字符串 ab*cd 中的 ab*c

Regular expressions use the backslash character ('') to indicate special forms or to allow special characters to be used without invoking their special meaning. This collides with Python’s usage of the same character for the same purpose in string literals; for example, to match a literal backslash, one might have to write '\\' as the pattern string, because the regular expression must be \, and each backslash must be expressed as \ inside a regular Python string literal.

其实也没看懂你到底要匹配哪种模式，不过你的问题上面的应该可以解决。
建议用raw string。