django中url无法include怎么配置?,djangoinclude,我有一个project


我有一个project 跟目录的root url conf 设置内容为:

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from django.conf.urls import patterns, include, urlimport funnytesturlpatterns = patterns(url(r'^funnytest/', include('funnytest.urls')),url(r'^helloworld/', funnytest.views.hello),)

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其中funnytest是其中一个app,funnytest 目录下设置了一个Urls, 内容为:
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from django.conf.urls import patterns, include, urlfrom views import *urlpatterns = patterns(url(r'^hello/$', hello),)

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我访问 localhost/funnytest/hello/ 会报错,表示urls 中没有匹配的配置
但是访问localhost/helloworld 是可以访问到view hello 的

为什么呢,应该如何配置~

应该这样写"url(r'^funnytest/', include('funnytest.urls',namespace="funnytest")),"

from django.conf.urls import patterns, include, urlfrom views import *urlpatterns = patterns(url(r'^hello/$', hello),)

第二个url写法是有问题的,导入模块写法应该是from app.views import hello这个格式,在django中,都应该这种导入方法。

另入,像第二个,我平时是这么写的:

url(r'^hello/$', 'app.viwes.hello`),

多看下django book里面的url写法。

http://stackoverflow.com/questions/12...

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