python yield生成器send发送数据问题,pythonyield,def countdow


def countdown(n):    print "conunting down form" ,n    while n>=0:        print "first n:",n         newvalue=(yield n)        print "second n:",n         print "first newvalue",newvalue        if newvalue is not None:            n=newvalue        else:            n-=1        print "second newvalue",newvaluec=countdown(5)for n in c:    # print n     if n==5:        c.send(3)

输出结果:
conunting down form 5
first n: 5
second n: 5
first newvalue 3
second newvalue 3
first n: 3
second n: 3
first newvalue None
second newvalue None
first n: 2
second n: 2
first newvalue None
second newvalue None
first n: 1
second n: 1
first newvalue None
second newvalue None
first n: 0
second n: 0
first newvalue None
second newvalue None

这个期间发送的send值是不是改变了n的值,是不是会继续进行n=3的迭代?

应该是send(3)作为(yield 5)的返回值,赋值给newvalue。所以操作完后newvalue==3,后续的n=newvalue导致n发生变化。

如果没有send操作,newvalue的值应该为None。send(3)作为(yield 5)的返回值,赋值给newvalue,所以n为3.从而导致后续的变化。值得注意的是yield n 会做为整个函数的返回值,而 newvalue = yield n,newvalue为None。

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