合并list和字典最不容易出错又简洁的python方法是什么？求解，容易出错python,我有2个字典,如下:a

字典貌似不应该这样用的吧……
我想给出的答案是

c = {k:d1[k]+d2[k] for d1,d2 in zip(a,b) for k in d1}

不过根据要求答案应该是

c = [{k:d1[k]+d2[k]} for d1,d2 in zip(a,b) for k in d1]

a中每个字典的值和b中每个字典的值对比，如果b中字典的值比a相应字典的值大，就copy过来，然后赋值给c.

>>> a = [{'s1': '2,1'}, {'s2': '1'}, {'s3': ''}, {'s4': ''}]>>> b = [{'s1': ''}, {'s2': ''}, {'s3': ''}, {'s4': '15,34'}]>>> for i in range(len(a)):        if cmp(a[i],b[i]) < 0:            a[i] = b[i].copy()        >>> c = a>>> print c[{'s1': '2,1'}, {'s2': '1'}, {'s3': ''}, {'s4': '15,34'}]