List pop([i]),listpop,# Remove the


# Remove the item at the given position in the list, and return it. If no index is # specified, a.pop() removes and returns the last item in the list. The item is # also removed from the list. (The square brackets around the i in the method # signature denote that the parameter is optional, not that you should type square # brackets at that position. You will see this notation frequently in the Python # Library Reference.) a = [66.25, 333, 333, 1, 1234.5]print a.pop(1)print a

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