Python中map filter reduce的递归实现，pythonreduce,map2=lambda

Python中map filter reduce的递归实现，pythonreduce,map2=lambda

map2=lambda f,seq: [] if seq==[] else [f(seq[0])] + map2(f, seq[1:])filter2=lambda f, seq: [] if seq==[] else ( [seq[0]]+filter2(f, seq[1:]) if f(seq[0]) else filter2(f, seq[1:]) )reduce2=lambda f,seq,x: x if seq==[] else reduce2(f, seq[1:], f(x, seq[0]))scanl=lambda f,seq,x: [x] if seq==[] else  [x] +scanl(f, seq[1:], f(x,seq[0]))print map2(str, [1,2,3,5,8])print filter2(lambda x: x%2==0, range(10))print reduce2(lambda x,y: ''.join( ['(',x,'+',y,')'] ), map(str,range(1,11)), '0')print scanl(lambda x,y: ''.join( ['(',x,'+',y,')'] ), map(str,range(1,5)), '0')#Out:#['1', '2', '3', '5', '8']#[0, 2, 4, 6, 8]#((((((((((0+1)+2)+3)+4)+5)+6)+7)+8)+9)+10)#['0', '(0+1)', '((0+1)+2)', '(((0+1)+2)+3)', '((((0+1)+2)+3)+4)']#该片段来自于http://byrx.net