python模拟ajax请求，获得ajax请求响应，pythonajax,有些网站的数据需要通过a

python模拟ajax请求，获得ajax请求响应，pythonajax,有些网站的数据需要通过a

有些网站的数据需要通过ajax来请求获得，ajax请求在发起请求之前必须设置必要的http头，还需要将请求数据封装为json格式。

如下代码片段：

def request_ajax_data(url,data,referer=None,**headers):    req = urllib2.Request(url)    req.add_header('Content-Type', 'application/x-www-form-urlencoded; charset=UTF-8')    req.add_header('X-Requested-With','XMLHttpRequest')    req.add_header('User-Agent','Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/27.0.1453.116')    if referer:        req.add_header('Referer',referer)    if headers:        for k in headers.keys():            req.add_header(k,headers[k])    params = urllib.urlencode(data)    response = urllib2.urlopen(req, params)    jsonText = response.read()    return json.loads(jsonText)

用法示例：

ajaxRequestBody = {"blogId":blogId,"postId":entryId,"blogApp":blogApp,"blogUserGuid":blogUserId}ajaxResponse = request_ajax_url('http://byrx.net/fakeAjax',ajaxRequestBody)