python实现同行内容匹配输出功能，python同行,python实现同行内容

python实现同行内容匹配输出功能，python同行,python实现同行内容

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1.[python实现同行内容匹配输出功能代码][Python]代码

#python版一行内容分行输出#依山居 18:14 2015/11/4a="aA1一bB2二cC3三dD4四eE5五fF6六gG7七hH8八iI9九""""分行输出为:abcdefghiABCDEFGHI123456789一二三四五六七八九"""print("方法一:===============")for r in range(0,4):    t=''    for s in range(0+r,len(a),4):        t=t+a[s]    print(t)print("方法二:===============")#=_=这个方法会不会看起来比较傻?l=list(a)ta=tb=tc=td=''for r in range(0,9):    for s in range(0,4):        if s==0:            ta=ta+l.pop(0)        if s==1:            tb=tb+l.pop(0)        if s==2:            tc=tc+l.pop(0)        if s==3:            td=td+l.pop(0)print(ta)print(tb)print(tc)print(td)      print("方法3:回字有N种写法===============")import stringta=tb=tc=td=''la=string.ascii_lowercaseua=string.ascii_uppercasenb=string.digitsub="一二三四五六七八九"for s in a:    if s in la:        ta=ta+s    if s in ua:        tb=tb+s    if s in nb:        tc=tc+s    if s in ub:        td=td+sprint(ta)print(tb)print(tc)print(td)print("方法4:回字有一种叫做正则的写法===============")import re#这正则写法感觉不科学,暂时没有好的想法reg=["[a-z]","[A-Z]","\d","[^\da-zA-Z]"]for s in reg:        rega=re.compile(s)    s=re.findall(rega,a)    print("".join(s))"""输出:方法一:===============abcdefghiABCDEFGHI123456789一二三四五六七八九方法二:===============abcdefghiABCDEFGHI123456789一二三四五六七八九方法3:回字有N种写法===============abcdefghiABCDEFGHI123456789一二三四五六七八九方法4:回字有一种叫做正则的写法===============abcdefghiABCDEFGHI123456789一二三四五六七八九"""

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