使用python编写微信跳一跳的自动脚本，python编写脚本,实现思路：调用adb

使用python编写微信跳一跳的自动脚本，python编写脚本,实现思路：调用adb

实现思路：

调用adb命令，截图寻找小小人的底部中心点role（从下到上扫描，直到找到小小人相同像素的点，至于小小人像素点rgb是什么，可以使用photoshop查看）寻找棋盘最高点top，然后寻找棋盘最右点。根据最高点与最右点，确定棋盘中心点border计算role与border之间的直线距离，然后设置按压时间=距离*按压系数调用adb 命令，按压屏幕

完整代码，测试机Oppo r11

#!/usr/bin/env python# -*- coding: utf-8 -*-from PIL import Image, ImageDrawimport mathimport osimport timeimport subprocess# 小小人底部RGBrole_bottom_rgb = (58, 58, 102)# 小小人头部RGBrole_top_rgb = (65, 65, 90)# 白色中心点 RGBwhite_point = (245, 245, 245)# 按压系数press_coefficient = 1.35def get_screenshot():    """    获取截图信息    :return:    """    process = subprocess.Popen(‘adb shell screencap -p‘, shell=True,                               stdout=subprocess.PIPE)    binary_screenshot = process.stdout.read()    binary_screenshot = binary_screenshot.replace(b‘\r\r\n‘, b‘\n‘)    with open(‘autojump.png‘, ‘wb‘) as f:        f.write(binary_screenshot)    time.sleep(1)    img = Image.open(‘autojump.png‘)    return imgdef is_similar(rgb1, rgb2, degree=20):    """    判断颜色是否相近    :param rgb1:    :param rgb2:    :param degree:    :return:    """    return abs(rgb1[0] - rgb2[0]) <= degree and abs(        rgb1[1] - rgb2[1]) <= degree and abs(rgb1[2] - rgb2[2]) <= degreedef calculate_jump_distance(img):    """    计算跳一跳的距离    :param image:    :return:    """    draw = ImageDraw.Draw(img)    im_pixel = img.load()    w, h = img.size    # 设置有效扫描区域    min_x = 100    max_x = w - 10    min_y = 400    max_y = h - 100    # step1:寻找小小人底座位置    role_start_x = 0    role_end_x = 0    role_y = 0    find_role = False    # y轴从下往上扫描    for y in range(max_y, min_y, -1):        # 找到小小人最低部一行，退出y轴循环        if find_role:            break        # y轴未找到最低一行，则继续遍历x轴元素点        # x轴从左到右扫描        for x in range(min_x, max_x):            current_rgb = im_pixel[x, y]  # 当前像素RGB值            # 寻找到小人底座首位像素点            if is_similar(current_rgb, role_bottom_rgb, 5):                if not find_role:  # 找到首位像素点                    find_role = True                    role_start_x = x                    role_y = y  # 小人底座中心点的y轴坐标已确定            # 小人底座最右侧像素点定位，条件：首位像素点已找到，在当前y轴上继续遍历x轴，当当前像素不在小小人中时，前一个像素点为底座最右点            if find_role and not is_similar(current_rgb, role_bottom_rgb, 5):                role_end_x = x - 1                break    # 小小人底座中心点    role_x = (role_start_x + role_end_x) / 2    role = (role_x, role_y)    draw.point([role], fill=(255, 0, 0))    # step2：寻找棋盘顶点：从上往下，从左到右扫描，寻找首位与初始点不一样的像素    # 解决小小人头部出现在最顶部时的BUG，在x轴扫描时，跳过小小人位置[role_start_x,role_end_x]    top_x = 0    top_y = 0    top_rgb = None    role_top_flag = False    for y in range(min_y, max_y):        for x in range(min_x, max_x):            current_rgb = im_pixel[x, y]            # 首先出现小小人的头部            if not role_top_flag:                if is_similar(current_rgb, role_top_rgb, 40):                    print("首先出现小小人头部！")                    role_top_flag = True                    continue                    # 当小小人头部在最顶部时，从上到下扫描时，当x处于小小人位置中时，跳过本次循环            if (role_start_x - 50 <= x <= role_end_x + 50) and role_top_flag:                # 当x轴坐标在小小人位置时                continue            # 顶部既不是小小人，又与初始像素点不一样，则定位为棋盘顶部，退出x轴扫描            if not is_similar(current_rgb, im_pixel[min_x, min_y],                              20):  # 与背景像素点不一样                top_x = x                # 解决棋盘边上出现一条乱七八糟颜色点将棋盘围起来时的BUG，找到第一个差异点后y轴继续往下5个像素点作为顶点                top_y = y + 4                top_rgb = im_pixel[top_x, top_y]                break        if top_rgb:  # 找到与初始点不一样的像素点，退出y轴循环            break    top = (top_x, top_y)    draw.point([top], fill=(255, 0, 0))    # step3：寻找棋盘最右侧点，条件：从top_x 向右，top_y 向下扫描，当与棋盘顶部像素点相似，x轴最大时，所在点为最右点    right_x = top_x    right_y = top_y    find_border = False    check_rgb = top_rgb    for x in range(top_x, max_x):        for y in range(top_y, max_y):            current_rgb = im_pixel[x, y]            # 找到相邻的相似元素点,定位条件：30个像素内，颜色相似            if is_similar(current_rgb, check_rgb, 20) and abs(                            x - right_x) <= 5 and abs(y - right_y) <= 5:                check_rgb = current_rgb                find_border = True                right_x = x                right_y = y                break        else:            # 如果当前y轴扫描完毕都没有遇到棋盘相似点（即没有遇到break），说明已经超出了最右侧棋盘点，退出x轴循环            if find_border:                break    right = (right_x, right_y)    draw.point([right], fill=(255, 0, 0))    # step4：定位棋盘中心：扫描棋盘，判断是否存在中心白点，否则初略可认为棋盘中心点位置是顶点和右侧点交叉位置    border = (top_x, right_y)    # 先排除初略中心点位置与白色中心点相似的情况，否则遇到白色版面会定位错误    if not is_similar(im_pixel[top_x, right_y], white_point, 4):        find_white_point = False        for y in range(top_y + 5, right_y + 5):            for x in range(top_x * 2 - right_x + 5, right_x - 5):                if is_similar(im_pixel[x, y], white_point, 2):                    # 寻找到白色中心点                    find_white_point = True                    border = (x, y + 10)                    print("寻找到白色中心点！")                    break            # 寻找到白色中心点，退出y轴循环            if find_white_point:                break    draw.point([border], fill=(255, 0, 0))    # draw.line([top, right], fill=(255, 0, 0), width=10)    draw.line([role, top, right, border], fill=(255, 0, 0), width=10)    # img.show()    img.save("debug.png")    return math.sqrt((role[0] - border[0]) ** 2 + (role[1] - border[1]) ** 2)def jump(distance):    press_time = distance * press_coefficient    press_time = max(press_time, 200)  # 设置 200ms 是最小的按压时间    press_time = int(press_time)    cmd = ‘adb shell input swipe 400 400 400 400 {duration}‘.format(        duration=press_time)    print(cmd)    os.system(cmd)    return press_timeif __name__ == ‘__main__‘:    i = 1    # img = get_screenshot()    # img=Image.open(‘autojump.png‘)    # distance = calculate_jump_distance(img)    # img.close()    # jump(distance)    while True:        img = get_screenshot()        distance = calculate_jump_distance(img)        jump(distance)        img.close()        i += 1        if i == 10:            time.sleep(2)        time.sleep(2)        print("*" * 100)

使用python编写微信跳一跳的自动脚本