Lintcode 37. Reverse 3-digit Integer 反转一个3位整数,digitcode
Lintcode 37. Reverse 3-digit Integer 反转一个3位整数,digitcode
class Solution: """ @param number: A 3-digit number. @return: Reversed number. """ def reverseInteger(self, number): return int(str(number)[::-1]) if __name__ == "__main__": a = input("输入3位整数: ") so = Solution() print(so.reverseInteger(a))
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