python3之利用字典和列表实现城市多级菜单,,利用字典和列表实现城


利用字典和列表实现城市多级菜单

 1 #coding:utf-8 2 #利用字典和列表实现城市多级菜单 3 addrIndex = {"1":"北京","2":"上海","3":"南京","4":"福建"} 4 addrDict = {"北京":["东城区","西城区","大兴区"],"上海":["黄浦区","长宁区","宝山区"],"南京":["玄武区","秦淮区","六合区"],"福建":["龙岩","泉州"]} 5 while True: 6     i = 1 7     #循环打印城市名称 8     for cs in addrDict.keys(): 9         print("%d.%s" %(i,cs))10         i += 111     choIndex = input("请输入你城市编号:")12 13     #为每个城市指定编号值,便于判断输入错误和扩展14     if choIndex not in addrIndex.keys():15         print("输入有误!")16         continue17     # print(addrDict[addrIndex[choIndex]])18 19     while True:20         i = 121         #根据输入的城市编号,获取城市名称,城市名称直接为addrDict字典的key22         for pq in addrDict[addrIndex[choIndex]]:23             print("%d.%s" %(i,pq))24             i += 125         pqCho = input("请输入片区编号,输入q返回上级:")26 27         #输入q跳出28         if pqCho == "q":29             break30         #输入正确的值打印,pqCho.isdigit()用于判断输入非q字符串错误31         elif pqCho.isdigit() and (int)(pqCho)-1>=0 and (int)(pqCho)-1<=len(addrDict[addrIndex[choIndex]])-1:32             print("你选择的是:%s" %(addrDict[addrIndex[choIndex]][(int)(pqCho)-1]))33         else:34             print("输入有误!")35             continue

python3之利用字典和列表实现城市多级菜单

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