欧拉计划(python) problem 6

欧拉计划(python) problem 6

Sum square difference

Problem 6

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 ? 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Python code :

n=100
sum=0
for i in range(1,n):
for j in range(i+1,n+1):
sum+=2*i*j
print(sum)

result :25164150

time :<1s