python3实践,, 需求name =


 需求

name = [‘wangxiaohua‘,‘wangdashu‘,6,9,9,80,‘haha‘,‘alex‘,34,34,‘wq‘,34,9,‘dfd‘,34,9,‘weew‘]
找出name列表中有多少个9并且全部将9修改成9999
找出所有的34并且全部删除

 思维导图

技术分享

 代码

name = [‘wangxiaohua‘,‘wangdashu‘,6,9,9,80,‘haha‘,‘alex‘,34,34,‘wq‘,34,9,‘dfd‘,34,9,‘weew‘]#将name列表中的所有9修改成9999for i in  range(name.count(9)):    position_of_ele = name.index(9)    name[position_of_ele] = 9999    print(name)    #删除name列表中的所有34元素for i in  range(name.count(34)):    position_of_ele = name.index(34)    name.remove(34)    print(name)#打印结果‘‘‘将全部9修改为9999[‘wangxiaohua‘, ‘wangdashu‘, 6, 9999, 9, 80, ‘haha‘, ‘alex‘, 34, 34, ‘wq‘, 34, 9, ‘dfd‘, 34, 9, ‘weew‘][‘wangxiaohua‘, ‘wangdashu‘, 6, 9999, 9999, 80, ‘haha‘, ‘alex‘, 34, 34, ‘wq‘, 34, 9, ‘dfd‘, 34, 9, ‘weew‘][‘wangxiaohua‘, ‘wangdashu‘, 6, 9999, 9999, 80, ‘haha‘, ‘alex‘, 34, 34, ‘wq‘, 34, 9999, ‘dfd‘, 34, 9, ‘weew‘][‘wangxiaohua‘, ‘wangdashu‘, 6, 9999, 9999, 80, ‘haha‘, ‘alex‘, 34, 34, ‘wq‘, 34, 9999, ‘dfd‘, 34, 9999, ‘weew‘]将34元素全部删除[‘wangxiaohua‘, ‘wangdashu‘, 6, 9999, 9999, 80, ‘haha‘, ‘alex‘, 34, ‘wq‘, 34, 9999, ‘dfd‘, 34, 9999, ‘weew‘][‘wangxiaohua‘, ‘wangdashu‘, 6, 9999, 9999, 80, ‘haha‘, ‘alex‘, ‘wq‘, 34, 9999, ‘dfd‘, 34, 9999, ‘weew‘][‘wangxiaohua‘, ‘wangdashu‘, 6, 9999, 9999, 80, ‘haha‘, ‘alex‘, ‘wq‘, 9999, ‘dfd‘, 34, 9999, ‘weew‘][‘wangxiaohua‘, ‘wangdashu‘, 6, 9999, 9999, 80, ‘haha‘, ‘alex‘, ‘wq‘, 9999, ‘dfd‘, 9999, ‘weew‘]‘‘‘

python3实践

评论关闭