python生成日历实例解析，python日历实例

文章由Byrx.net分享于2019-03-22 05:03:15评论（237）

python生成日历实例解析，python日历实例

本文实例展示了Python生成日历的实现方法。该实例可实现一个月的日历生成5x7的列表，列表里的没个日期为datetime类型，采用python自带的 calendar 模块实现。

程序运行结果如下：

python test.py 2014 09 
2014-08-31 2014-09-01 2014-09-02 2014-09-03 2014-09-04 2014-09-05 2014-09-06 
2014-09-07 2014-09-08 2014-09-09 2014-09-10 2014-09-11 2014-09-12 2014-09-13 
2014-09-14 2014-09-15 2014-09-16 2014-09-17 2014-09-18 2014-09-19 2014-09-20 
2014-09-21 2014-09-22 2014-09-23 2014-09-24 2014-09-25 2014-09-26 2014-09-27 
2014-09-28 2014-09-29 2014-09-30 2014-10-01 2014-10-02 2014-10-03 2014-10-04

python代码如下：

#coding:utf-8
# Last modified: 2014-08-21 11:08:08 
import calendar 
import datetime 
import sys 
 
def getcal(y, m): 
 # 从周日开始 
 cal = calendar.Calendar(6) 
 if not isinstance(y, int): y = int(y) 
 if not isinstance(m, int): m = int(m) 
 if m == 1: # 1月份 
  py = y - 1; pm = 12; 
  ny = y; nm = 2 
 elif m == 12: # 12月份 
  py = y; pm = 11 
  ny = y + 1; nm = 1 
 else: 
  py = y; pm = m - 1 
  ny = y; nm = m + 1 
 pcal = cal.monthdayscalendar(py, pm) # 上一月 
 ncal = cal.monthdayscalendar(ny, nm) # 下一月 
 ccal = cal.monthdayscalendar(y, m)  # 当前 
 w1 = ccal.pop(0) # 取第一周 
 w2 = ccal.pop() # 取最后一周 
 wp = pcal.pop() # 上个月的最后一周 
 wn = ncal.pop(0) # 下个月的第一周 
 #r1 = [datetime.date(y, m ,w1[i]) or wp[i] for i in range(7)] 
 r1 = [w1[i] and datetime.date(y, m, w1[i]) or datetime.date(py, pm, wp[i]) for i in range(7)] 
 r2 = [w2[i] and datetime.date(y, m, w2[i]) or datetime.date(ny, nm, wn[i]) for i in range(7)] 
 # 转datetime 
 result = [] 
 result.append(r1) # 第一周 
 for c in ccal:  # 其他周 
  result.append([datetime.date(y,m,i) for i in c]) 
 result.append(r2) # 最后一周 
 return result 
 
if __name__ == '__main__': 
 for w in getcal(sys.argv[1], sys.argv[2]): 
  for d in w: 
   print d, 
  print

希望本文所述实例对大家的Python程序设计有所帮助。

python中怎把日历按照下面格式输出？

import calendar

c = calendar.TextCalendar(6)
print c.prmonth(2011, 11)

怎在python写查询日历的程序不引用模块

#!/usr/bin/evn python

def simpleCalendar():
daysOfMonth=daysOfMonths=daysOfYears=month=year=0
yearfun=lambda year:year % 400 ==0 or year % 4==0 and year % 100 !=0
print "*"*30,"calendar","*"*30
year=input("enter year: ")
leap=yearfun(year)
month=input('enter month: ')
assert month in range(1,13),"month must in 1-12"
if month==2:
daysOfMonth=29 if leap else 28
else:
daysOfMonth=30 if month in [4,6,9,11] else 31

for i in range(1,month):
if i==2:
daysOfMonths+=29 if leap else 28
else:
daysOfMonths+=30 if i in [4,6,9,11] else 31

for i in range(1900,year):
daysOfYears+=366 if yearfun(i) else 365
daysOfYears+=daysOfMonths
weak=1+daysOfYears%7
print "Sun\tMon\tTue\tWed\tThu\tFri\tSat"
print "\t"*weak,
for i in range(1,daysOfMonth+1):
weak+=1
if weak%7!=0:
print i,'\t',
else:
print i,'\n',

if __name__=='__main__':
simpleCalendar()

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python生成日历实例解析，python日历实例