for循环方式完成列表分区间统计效果报错，求解，for分区,list= [ .

文章由Byrx.net分享于2019-03-23 07:03:43评论（312）

for循环方式完成列表分区间统计效果报错，求解，for分区,list= [ .


list= [    ...,    2648, 2648, 2648, 63370, 63370, 425, 425, 120,    120, 217, 217, 189, 189, 128, 128, 115, 115, 197,    19752, 152, 152, 275, 275, 1716, 1716, 131, 131,    98, 98, 138, 138, 277, 277, 849, 302, 152, 1571,    68, 68, 102, 102, 92, 92, 146, 146, 155, 155,    9181, 9181, 474, 449, 98, 98, 59, 59, 295, 101,    ...]for i in list:    if int(i/50)+1 not in dic:        dic(int(i /50)+1)=list.count(i)    else:        dic(int(i /50)+1)+=list.count(i)

我这么写总是报错，我想以 50bp 为一个区间进行统计，即统计长度在 0-50 的频数，50-100 的频数...

我这么写对么，应该怎么写呢?

# code for python3from itertools import groupbylst= [    2648, 2648, 2648, 63370, 63370, 425, 425, 120,    120, 217, 217, 189, 189, 128, 128, 115, 115, 197,    19752, 152, 152, 275, 275, 1716, 1716, 131, 131,    98, 98, 138, 138, 277, 277, 849, 302, 152, 1571,    68, 68, 102, 102, 92, 92, 146, 146, 155, 155,    9181, 9181, 474, 449, 98, 98, 59, 59, 295, 101, 5]for k, g in groupby(sorted(lst), key=lambda x: x//50):    print('{}-{}: {}'.format(k*50, (k+1)*50-1, len(list(g))))

結果:

0-49: 150-99: 10100-149: 15150-199: 8200-249: 2250-299: 5300-349: 1400-449: 3450-499: 1800-849: 11550-1599: 11700-1749: 22600-2649: 39150-9199: 219750-19799: 163350-63399: 2

我回答過的問題: Python-QA

for i in list i是list中的内容，应该是for I in range(len(list))

编橙之家文章，

相关内容

评论关闭

最新python问答

python~HOT