Coding the Matrix作业Python Lab及提交方法


Coding the Matrix: Linear Algebra through Computer Science Applications
  这是一门用python实现矩阵运算的课,第一次作业就感觉对python的提高很大,用到了各种数据类型。

  代码如下:

## Task 1   
minutes_in_week = 60*24*7  
  
## Task 2   
remainder_without_mod = 2304811-2304811//47*47  
  
## Task 3   
divisible_by_3 = (673+909)/3==0  
  
## Task 4   
x = -9  
y = 1/2  
statement_val = 2**(y+1/2) if x+10<0 else 2**(y-1/2)  
  
## Task 5   
first_five_squares = { x*x for x in {1,2,3,4,5} }  
  
## Task 6   
first_five_pows_two = { 2**x for x in {0,1,2,3,4} }  
  
## Task 7: enter in the two new sets   
X1 = { 1, 2, 3 }  
Y1 = { 4, 11, 17 }  
  
## Task 8: enter in the two new sets   
X2 = { 1, 2, 0 }  
Y2 = { 4, 8, 16 }  
  
## Task 9   
base = 10  
digits = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}  
three_digits_set = { base**2*x+base*y+z for x in digits for y in digits for z in digits }  
  
## Task 10   
S = {1, 2, 3, 4}  
T = {3, 4, 5, 6}  
S_intersect_T = { x for x in S if x in T }  
  
## Task 11   
L_average = sum([20, 10, 15, 75])/len([20, 10, 15, 75]) # average of: [20, 10, 15, 75]   
  
## Task 12   
LofL = [[.25, .75, .1], [-1, 0], [4, 4, 4, 4]]  
LofL_sum = sum({sum(LofL[x]) for x in range(0,len(LofL))}) # use form: sum([sum(...) ... ])   
  
## Task 13   
cartesian_product = [[x,y] for x in {'A','B','C'} for y in {1,2,3} ] # use form: [ ... {'A','B','C'} ... {1,2,3} ... ]   
  
## Task 14   
S = {-4, -2, 1, 2, 5, 0}  
zero_sum_list = [ (x,y,z) for x in S for y in S for z in S if x+y+z==0 ]   
  
## Task 15   
exclude_zero_list = [ (x,y,z) for x in S for y in S for z in S if (x+y+z==0) and (x or y or z) ]  
  
## Task 16   
first_of_tuples_list = [ (x,y,z) for x in S for y in S for z in S if (x+y+z==0) and (x or y or z) ][0]  
  
## Task 17   
L1 = [1,1,2] # <-- want len(L1) != len(list(set(L1)))   
L2 = [2,1,3] # <-- same len(L2) == len(list(set(L2))) but L2 != list(set(L2))   
  
## Task 18   
odd_num_list_range = { x for x in range(1,100,2)}  
  
## Task 19   
L = ['A','B','C','D','E']  
range_and_zip = list(zip(list(range(5)),L))  
  
## Task 20   
list_sum_zip = [x+y for (x,y) in zip([10,25,40],[1,15,20])]  
  
## Task 21   
dlist = [{'James':'Sean', 'director':'Terence'}, {'James':'Roger', 'director':'Lewis'}, {'James':'Pierce', 'director':'Roger'}]  
k = 'James'  
value_list = [d[k] for d in dlist]  
  
## Task 22   
dlist = [{'Bilbo':'Ian','Frodo':'Elijah'},{'Bilbo':'Martin','Thorin':'Richard'}]  
k = 'Bilbo'  
value_list_modified_1 = [d[k] if k in d else 'NOT PRESENT' for d in dlist] # <-- Use the same expression here   
k = 'Frodo'  
value_list_modified_2 = [d[k] if k in d else 'NOT PRESENT' for d in dlist] # <-- as you do here   
  
## Task 23   
square_dict = {x:x**2 for x in range(100)}  
  
## Task 24   
D = {'red','white','blue'}  
identity_dict = {x:x for x in D}  
  
## Task 25   
base = 10  
digits = set(range(10))  
representation_dict = { base**2*x+base*y+z:[x,y,z] for x in digits for y in digits for z in digits}  
  
## Task 26   
d = {0:1000.0, 1:1200.50, 2:990}  
names = ['Larry', 'Curly', 'Moe']  
listdict2dict = { names[x]:y for (x,y) in d.items() }  
  
## Task 27   
def nextInts(L): return [ x+1 for x in L ]  
  
## Task 28   
def cubes(L): return [ x**3 for x in L ]   
  
## Task 29   
def dict2list(dct, keylist): return [ dct[x] for x in keylist ]  
  
## Task 30    
def list2dict(L, keylist): return { x:y for (x,y) in zip(keylist,L) }   

  评分系统有一些bug,如task2不能用括号等,如果出错可以比对一下。

  提交方法:
  在linux下提交按照说明即可,但在windows下面,就要费好大一番功夫了。

  由于submit_python_lab.py里面默认待提交的py文件在当前目录下,必须把py文件和submit_python_lab.py文件拷贝到python3的安装文件夹下面。我用的是python3.3,因此要拷贝到的目录为:C:\Python33。论坛说双击submit_python_lab.py输入账号密码即可,为了方便我使用bat脚本文件运行:

 

C:\Python33\python C:\Python33\submit_python_lab.py  

 

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