python实现三级菜单，,多级菜单实现任务：三

python实现三级菜单，,多级菜单实现任务：三

多级菜单实现任务：三级菜单可依次选择进入各子菜单所需新知识点：列表、字典

代码实现：

 1 #Author:AZ 2  3 data = { 4     ‘北京‘:{ 5         "昌平":{ 6             "沙河":["old boy","test"], 7             "天通苑":["链家地产","我爱我家"] 8         }, 9         "朝阳":{10             "望京":["奔驰","陌陌"],11             "国贸":["CICC","HP"],12             "东直门":["Advent","飞信"]13         },14         "海淀":[]15     },16     ‘陕西‘:{17         "西安":{18             "雁塔区":["大雁塔"],19             "曲江新区":["大唐芙蓉园"]20         },21         "汉中":{22             "汉台区":["汉大","拜将坛"],23             "洋县":["油菜花"]24         },25         "宝鸡":[]26     },27     ‘河南‘:{28         "郑州":{29             "二七":["银河世纪","人民公园"],30             "金水区":["郑大"]31         },32         "商丘":{33             "古城":["归德府","火神台"],34             "高中":["二高","一高","四高"]35         },36         "洛阳":{37             "洛龙区":["龙门石窟"],38             "栾川县":["老君山"]39 40         }41     },42 43 }44 exit_flag = False45 46 while not exit_flag:47     for i in data:48         print(i)49     choice = input("选择进入1>>>:")50     if choice in data:51         while not exit_flag:52             for i2 in data[choice]:53                 print("\t",i2)54             choice2 = input("选择输入2>>:")55             if choice2 in data[choice]:56                 while not exit_flag:57                     for i3 in data[choice][choice2]:58                         print("\t\t",i3)59                     choice3 = input("选择进入3>>:")60                     if choice3 in data[choice][choice2]:61                         for i4 in data[choice][choice2][choice3]:62                             print("\t\t",i4)63                         choice4 = input("最后一层，按b返回>>:")64                         if choice4=="b":65                             pass66                         elif choice4==‘q‘:67                             exit_flag=True68                     if choice3==‘b‘:69                         break70                     elif choice3 =="q":71                         exit_flag=True72             if choice2 ==‘b‘:73                 break74             elif choice2=="q":75                 exit_flag = True

3level_menus.py

python实现三级菜单