计算日期差(Python实现),,class Solu


class Solution:    def Days(self,year,month,day):        if  (year%4==0 and year%100!=0) or year%400==0:            monthlist=[0,31,29,31,30,31,30,31,31,30,31,30,31]        else:            monthlist=[0,31,28,31,30,31,30,31,31,30,31,30,31]        years=year-1        days=years*365+years/4-years/100+years/400        for i in range(0,month):            monthdays=monthdays+monthlist[i]        days=days+monthdays+day        return days    def SubDays(year1,month1,day1,year2,month2,day2):        days1=Days(year1,month1,day1)        days2=Days(year2,month2,day2)        subday=days1-days2        print subday

  

计算日期差(Python实现)

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